0=-16t^2-24t+1400

Solution for 0=-16t^2-24t+1400 equation:

0=-16t^2-24t+1400

We move all terms to the left:

0-(-16t^2-24t+1400)=0

We add all the numbers together, and all the variables

-(-16t^2-24t+1400)=0

We get rid of parentheses

16t^2+24t-1400=0

a = 16; b = 24; c = -1400;
Δ = b2-4ac
Δ = 242-4·16·(-1400)
Δ = 90176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{90176}=\sqrt{64*1409}=\sqrt{64}*\sqrt{1409}=8\sqrt{1409}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-8\sqrt{1409}}{2*16}=\frac{-24-8\sqrt{1409}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+8\sqrt{1409}}{2*16}=\frac{-24+8\sqrt{1409}}{32}
$